How many geometrical isomers and stereoisomer | vedclass

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Question

(B) For the square planar complex $[Pt(abcd)]^+$,the number of geometrical isomers is $3$. These are the arrangements where pairs of ligands are trans

Vedclass · Accepted Answer

$3$ and $30$

Vedclass · Answer

(B) For the square planar complex $[Pt(abcd)]^+$,the number of geometrical isomers is $3$. These are the arrangements where pairs of ligands are trans to each other: $(a,b), (a,c), (a,d)$.For the octahedral complex $[Pt(abcdef)]$,the number of geometrical isomers is $15$. Since all ligands are different,each geometrical isomer exists as a pair of enantiomers (optical isomers). Therefore,the total number of stereoisomers is $15 	imes 2 = 30$.

How many geometrical isomers and stereoisomers are possible for $[Pt(NO_2)(NH_3)(NH_2OH)(Py)]^+$ and $[Pt(Br)(Cl)(I)(NO_2)(NH_3)(Py)]$ respectively?

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